In a gripping match, Alexander Zverev secured his place in the semi-finals of the Australian Open, defeating American Tommy Paul in a four-set contest. The German star showed remarkable dominance and great composure, clinching the match with a score of 7-6 (7-1), 7-6 (7-0), 2-6, 6-1, strengthening his position as a serious contender for the title.
Ranked second in the world, Zverev faced a determined challenge from Paul, who showed notable resilience and agility throughout the encounter. The first set was thrilling, extending to a tense tiebreak where Zverev asserted his dominance, winning 7-1. Despite falling behind 4-1 in the second set, Zverev rallied to secure another tiebreak, triumphing 7-0 and taking a 2-0 lead.
Paul responded strongly in the third set, outplaying Zverev to win it 6-2. However, the German regained his momentum in the fourth set, controlling the match with a convincing 6-1 victory to complete his progress.
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Zverev reaches Australian Open semi-finals after victory over Paul
Throughout the match, Zverev’s powerful serve and precision were in evidence, winning 24 of the first 30 service points, effectively exploiting Paul’s waning energy.
Following this significant victory, Zverev now turns his attention to the next semi-final, where he will face the winner of the highly anticipated clash between Carlos Alcaraz and Novak Djokovic. With both opponents in great form, Zverev’s recent performance makes him a strong contender for the coveted title in Melbourne.
